Question

b+c/a,c+a/b,a+b/c are in a.p
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Answer 1

Answer:

hope it help

Step-by-step explanation:

(i) 1/a, 1/b, 1/c are in AP If 1/a, 1/b, 1/c are in AP then, 1/b – 1/a = 1/c – 1/b Let us consider LHS: 1/b – 1/a = (a - b)/ab = c(a - b)/abc [by multiplying with ‘c’ on both the numerator and denominator] Let us consider RHS: 1/c – 1/b = (b - c)/bc = a(b - c)/bc [by multiplying with ‘a’ on both the numerator and denominator] Since, (b + c)/a, (c + a)/b, (a + b)/c are in AP a(b - c) = c(a - b) LHS = RHS Hence, the given terms are in A.PRead more on Sarthaks.com - https://www.sarthaks.com/802861/if-b-c-a-c-a-b-a-b-c-are-in-ap-prove-that-i-1-a-1-b-1-c-are-in-ap-ii-bc-ca-ab-are-in-ap