Math, asked by sheeshrambjr, 5 months ago

b+c-a tanA/2= c+a-b tanB/2=a+b-c tanC/2.​

Answers

Answered by jasskaur7518
0

Answer:

(b + c - a)tanA/2 = (c + a - b)tanB/2 = (a + b - c)tanC/2 b + c - a = 2(s - a) c + a - b = 2(s - b) a + b - c = 2(s - c) r = (s - a)tan(A/2) Hence proved

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