Question

b+c-a/y+z-x=c+a-b/z+x-y=a+b-c/x+y-z, then prove that a/x=b/y=c/z​

Answer 1

Answer:

Step-by-step explanation:

b+c-a/y+z-x=c+a-b/z+x-y=a+b-c/x+y-z

=(b/y+z-x)+(c/y+z-x)-(a/y+z-x)=(c/z+x-y)+(a/z+x-y)-(b/z+x-y)=(a/x+y-z)+(b/x+y-z)-(c/x+y-z)

=a/x=b/y=c/z(proved)