Question

b(c-d)^2 +a(d-c)+(c-d)

Answer 1

$\textbf{Answer :}$

Now,

b (c - d)² + a (d - c) + (c - d)

= b (c - d)² - a (c - d) + (c - d)

= (c - d) {b (c - d) - a + 1}

= (c - d) (bc - bd - a + 1),

which is the required factorization.

#$\textbf{MarkAsBrainliest}$

Answer 2

Bonjour!

=> b(c - d)² + a(d - c) + (c - d)

=> b(c - d)(c - d) - a(c - d) + (c - d)

=> (c - d)(b(c - d) - a + 1)

=> (c - d)(bc - bd - a + 1)

Hope this helps...:)