Question

B+C
Prove in a triangle ABC that cos
2
sin
2
Tin
А
2​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

We have,

c

a+b

=

2RsinC

2R(sinA+sinB)

[ Using sine rule of triangle]

=

sinC

sinA+sinB

=

2.sin

2

C

.cos

2

C

2.sin

2

A+B

.cos

2

A−B

=

sin

2

C

.cos

2

C

sin(

2

π

−

2

C

).cos

2

A−B

[ Since A+B+C=180

o

]

=

sin

2

C

.cos

2

C

cos

2

C

.cos

2

A−B

=

sin

2

C

cos

2

A−B