Question

(b-c)x2+2(c-a)x+(a-b)=0 show the roots are always real

Answer 1

2x(b-c+c-a)+(a-b)=0
2x(b-a)=-(a-b)
2x=b-a/b-a
2x=1
X=1/2

Answer 2

(b-c)×4 (c-a) x+(a-b)=0
4b-4c×4c-4ax+a-b=0
4b-16c-4a x+a-b=0