(b-c)x2+(c-a)x+(a-b)=0
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Answered by
2
(b-c)*2+(c-a)x+(a-b)=0
2b-2c+xc-ax+a-b=0
b-2c+xc-ax+a=0
b=2c-xc+ax-a
please mark my answer as brainliest.
2b-2c+xc-ax+a-b=0
b-2c+xc-ax+a=0
b=2c-xc+ax-a
please mark my answer as brainliest.
Answered by
3
2(b-c)+(c-a)x+(a-b)=0
⇒ 2b-2c+xc-ax+a-b=0
⇒ b-2c+xc-ax+a=0
⇒ b=2c-xc+ax-a
⇒ 2b-2c+xc-ax+a-b=0
⇒ b-2c+xc-ax+a=0
⇒ b=2c-xc+ax-a
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