Question

(b)Calcualte the ratio of magnetic field at a point a/2 above the surface of the
wire to that at a point a/2 below its surface. What is the maximum value of
the field of this wire ?​

Answer 1

Answer:

Calculate the ratio of magnetic field at a point a/2 above the surface of the wire to that at a point a/2 below its surface. What is the maximum value of the field of this wire? =a+a/2=3a/2. r′=a-a/2=a/2.

Answer 2

$B_{outside} = U_{o}I/2\pi a$.

Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Step 1:

$B_{outside} = U_{o}I/ 2\pi r = U_{o}I / 2\pi (a+a/2) = U_{o}I/ 3\pi a$

Step 2:

$B_{inside}= U_{o}Ir/2\pi a ^{2} = U_{o}I(a/2)/2\pi a^{2} = U_{o}I/4\pi a$

Step 3:

$B_{outside}/ B_{inside} = 4/3$  

$B_{outside} = U_{o}I/2\pi a$.

Maximum value of magnetic field is at the surface given by $B_{outside} = U_{o}I/2\pi a$.

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