Question

(b) Calculate the mass in grams of 3.01 x 1020 molecules of glucose
(CH20).
(Ans: 0.09 grams]
A compound of Hand N coprainc 660​

Answer 1

Explanation:

No. of particles / Avogadro's number =Mass of substance/ Molecular mass

No. of particles = 3.01 × 10^20

Avogadro's Number = 6.02 × 10^23

Molecular mass of glucose ( C6 H12 O6 ) = 12×6 + 12 × 1 + 16 × 6 = 72 + 12 + 96 = 180 g.

So , mass of the substance is ,

$\frac{3.01 \times {10}^{20} }{6.02 \times {10}^{23} } = \frac{mass}{180}$

$mass = \frac{180}{2000} = 0.09 g$

Hence , the mass of glucose is 0.09 g.

I hope it helps you. If you have any doubts, then don't hesitate to ask.

Answer 2

Answer:

please mark as brainlist

Explanation:

No. of particles / Avogadro's number =Mass of substance/ Molecular mass

No. of particles = 3.01 × 10^20

Avogadro's Number = 6.02 × 10^23

Molecular mass of glucose ( C6 H12 O6 ) = 12×6 + 12 × 1 + 16 × 6 = 72 + 12 + 96 = 180 g.

So , mass of the substance is ,

\frac{3.01 \times {10}^{20} }{6.02 \times {10}^{23} } = \frac{mass}{180}

6.02×10

23

3.01×10

20

=

180

mass

mass = \frac{180}{2000} = 0.09 gmass=

2000

180

=0.09g

Hence , the mass of glucose is 0.09 g.

I hope it helps you. If you have any doubts, then don't hesitate