Question

(b)Calculate the number of particles in the following-(given atomic masses Mg =24u,N=14u)
i-2.4 g of Mg atoms ii- 0.5mole of N2 gas

please give proper explanation

Answer 1

Answer:

(i) 0.6022 × 10²³ particles

(ii) 3.011 × 10²³ particles

Explanation:

1 mole of any substance contains Avogadro's number of particles.

Avogadro's number = 6.022 × 10²³

(i) Given atomic mass of Mg = 24 u

Molar mass of Mg (mass of 1 mole of Mg) = 24 g

Now,

24 grams of Mg contains = Avogadro's number of Mg = 6.022 × 10²³ particles

2.4 grams of Mg contains = (6.022 × 10²³ ) / 24 × 2.4 particles

2.4 grams of Mg contains = 0.6022 × 10²³ particles.

(ii) Given mass of N atom = 14 u

1 mole of N2 contains = Avogadro's number of N2 = 6.022 × 10²³ particles

0.5 mole of N2 contains = 0.5 × 6.022 × 10²³ particles

0.5 mole of N2 contains = 3.011 × 10²³ particles.