(b) Calculate the relative molecular masses of:-
(i)CHCI3 (ii) CuSOa. 5H2O (iii) CH3COO Na
(C= 12, Fl = 1", Cl = 35.5, Cu = 63.5, S = 32, O = 16, Na = 23)
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Answer:
(i) CHCl3
molecular mass = (C) + (H) + 3×(Cl?
molecular mass = (12) + (1) + 3×(35.5) = 119.5
(ii) CuSO4.5H2O
molecular mass = (Cu) + (S) + 4×(O) + 5×{ 2×(H) + (O) }
molecular mass = 63.5 + 32 + 4(16) + 5{ 2(1) + 16 }
molecular mass = 95.5 + 64 + 5(2+16)
molecular mass = 249.5
(iii) CH3COONa
molecular mass = (C) + 3×(H) + (C) + 2×(O) + (Na)
molecular mass = (12) + 3(1) + 12 + 2×(16) + 23
molecular mass = 82
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