Question

b. Calculate total energy consumed per day by the use of following loads:
i) 5 number of 40 W lights operated 5 hours per day
ii) 1 h.p. motor is operated 2 hours per day
iii) 1 k.W heater is operated 1 hour per day
iv) 1 computer is used for 6 hours per day with printer about 30 minutes.​

Answer 1

Answer:

Answer

Energy = Power*time

Energy consumed by 100 W bulb per day = 2∗100 Wh

= 0.2 kWh

Energy consumed by 40 W bulbs per day = 4∗40∗4 Wh

= 0.64 kWh

Total energy consumed per day = 0.2 + 0.64 kWh

= 0.84 kWh

Therefore, the energy consumed in 30 days = 30∗0.84 kWh

= 25.2 kWh

Answer 2

Concept:

Energy, consumed (E)= (P*t)/1000 kWh

Where P is the power given in Watts

And t is time given in hours.

i)

    given:

    P= 5 *40 =200 W

    T= 5 h

    find: Energy consumed

    Solution:

    E= (200 * 5 )/1000 =2 kWh

ii)

    given:

    P= 1 h.p = 735.499W

    T= 2hr

    find: Energy consumed

    Solution:

    E= (735.5 * 2)/1000 = 1.47 kWh

iii)

    given:

    P= 1 kW =1000 W

    T= 1 h

    find: Energy consumed

    Solution:

    E = (1000 * 1)/1000=1 kWh

iv)

    Since power consumption is not given so let us make a few               assumption

    P1 = power consumed by computer =100 W

    P2 =power consumed by printer= 50 W

    given:

    T1= Computer uses time = 6h

    T2= Printer Uses Time= 30 min = 0.5 h

    find: Energy consumed

    Solution:

    E= (p1*t1 + p2*t2)/1000

    E= (100*6 + 50*0.5)/1000 = 0.625 kWh

#SPJ2