B can complete the work in 30 days, if A is 50% more efficient than B and C is 25% less efficient than B, in how many days will all 3 of them complete the work?
Answers
all 3 of them together complete the work in 120/13 days
Step-by-step explanation:
B can complete the work in 30 days,
B's 1 day work = 1/30
A is 50% more efficient than B
=> A's 1 day work = 1/30 + (50/100)(1/30)
= 1/30 + 1/60
= 3/60
= 1/20
C is 25% less efficient than B
=> C's 1 day work = 1/30 - (25/100)(1/30)
= 1/30 - 1/120
= (4 - 1)/120
= 3/120
= 1/40
A B & C together 1 day work = 1/30 + 1/20 + 1/40
= (4 + 6 + 3)/120
= 13/120
they will complete the work in 120/13 days
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Answer:
120/13
experimental -:
hope you know your answer