b) Construct a triangle ABC in which AB=5 cm, BC=7 cm and
<B= 60° construct triangle, such that each side of the new
triangle is 5/4 of the triangle ABC.
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The construction will be as follows and new triangle is 5/4 times the old one.
Hope it helps U
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Triangle A'BC' is the required triangle.
Step-by-step explanation:
- Draw a line segment BC = 7 cm. Draw an arc of any radius while taking B as centre. Let it intersect line BC at point O. Now taking O as centre draw another arc to cut the previous arc at point O'. Joint BO' which is the ray making 60° with line BC.
- Now draw an arc of 5 cm. radius, while taking, B as centre, intersecting extended line segment BO' at point A. Join AC. Triangle ABC is having AB = 5 cm.
- draw a ray BX making an acute angle with BC on opposite side of vertex A.
- Locate 5 points B1, B2, B3, B4, B5 on line segment BX.
- Join B5C and draw a line through B4, parallel to B5C intersecting BC at C'.
- Draw a line through C' parallel to AC intersecting AB at A'. Triangle A'BC' is the required triangle.
#Learn more:
Construct a triangle ABC in which AB = 3Ccm and BC= 5 cm and Ca = 6 cm .Construct a triangle A'BC' similar to triangle ABC with BC' = 7cm
https://brainly.in/question/12768329
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