Question

b) Construct the right-angled APQR, where LQ = 90°, QR = 6 cm and PR = 10 cm.​

Answer 1

Step-by-step explanation:

To construct the triangle we need to find the value of remaining side that is PQ which can be done through Pythagoras therom

PR²=PQ²+QR²

10²= PQ² +6²

100= PQ² +36

PQ²=100-36=64

PQ=8 Hence triangle can be drawn easily