Math, asked by karansingh000100020, 4 months ago


b) Construct the right-angled APQR, where LQ = 90°, QR = 6 cm and PR = 10 cm.
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Answers

Answered by Anonymous
4

Step-by-step explanation:

Step 1. Draw a line QR=8 cm

Step 2. At point Q ,draw an angle of 90 ∘

Step 3. From R cut an arc PR=10 cm using compass.

Step 4. Name the point of intersection of the arm of angle 90∘ and the arc in step 3 , as P

Step 5. Join P to Q. PQR is required triangle.

So the second step is 1

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Answered by amritlalahirwar12345
1

Answer:

1. Draw a line segment QR of length 8cm

2. Now we draw 90° from point Q

3. Taking R as center,10cm as radius, we draw an arc let the point where arc intersects the ray be point P

4. Join PR and label the sides

Thus,∆ PQR is the required triangle.

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