Question

B cos theta=A prove that cosec theta+cot theta=whole SQ B+A/A-B​

Answer 1

Answer:

bcosx= a

=> Cosx = a/b = B/H

P = √ (H²-B²)

P= √(b²-a²)

cosecx = H/P = b/√(b²-a²)—(1)

cotx = B/P = a/√(b²-à²)——(2)

Adding (1) and (2)

cosecx + cotx = b+a/√(b²-a²)

cosecx + cotx = √(b+a)²/(b²-a²)

cosecx + cotx = √(b+a)/(b-a) ……Hence proved