Chemistry, asked by ansikapare7, 4 months ago


b) Derive an expression for kinetic energy for an object of mass 'm'
moving with a velocity 'v'.

Answers

Answered by Abhijeetroy
1

Explanation:

Kinetic Energy:

The energy possessed by an object due to its motion is called as kinetic energy.

Derivation:

Let us consider an object of mass "m" which is at rest on smooth horizontal plane.

Let a Force ,F acts on the object and let the object from rest moves from point A to point B and covers a displacement S.

The Work done by Force on the object is :

Workdone = Force x displacement.

W=F×S ____(1).

From third equation of motion;

V

2

−U

2

=2aS

S=

2a

V

2

−U

2

______(2)

By Newtons second law of motion:

F=ma

From equation 1 and 2

W=

2a

m∗a∗(V

2

−U

2

)

As we have assumed object is at rest, U=0

W=

2

mV

2

The Work Done appears as kinetic energy of the body.

Therefore,

K.E=(

2

1

)mV

2

Answered by lalipapa123
1

Explanation:

Kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

we will consider an object of m which is at rest lying on a table.

Let A force F acts on the object which moves the object through a distance S.

The workdone=F×S

W=Fnet×S-------(1)

Let the work done on the object causes a change in its velocity from u to V and let a be the acceleration.

From Third equation of motion:

V²−u²=2as

s=V²−u²/2a----------(2)

By Newton's Second law:

F=ma------(3)

From equation (1), (2) and (3)

W=ma×(V2−u2/2a)=(1/2)m(V2−u2)

As we assumed object at rest, u=0

W=(1/2)mV2

we know that the kinetic energy of a body moving with a certain velocity is equal to work done on the object to acquire that velocity from rest.

∴K.E=1/2mV2

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