Question

(b) Discuss the effect of temperature on the spontaneity of an exothermic
reaction.​

Answer 1

$\huge\fbox\color{purple}Answer:-✍$

How is the spontaneity of an exothermic reaction changed when temperature is decreased?

Assuming the entropy is negative. ... However, using Le Chatelier's principle, as temperature decreases the reaction should shift towards the right towards the products, becoming more spontaneous.

Explanation:

The key is

ΔG=−RTln⁡K

.

specifically is causing your reasoning to be flawed, as it complicates the link between temperature dependence of the equilibrium constant and

−RTln⁡K=ΔH−TΔS

−Rln⁡K=ΔHT−ΔS

In this form you can see that (at least to the extent that are temperature independent), the sign of are temperature independent), the sign of (meaning whether the reaction is endothermic or exothermic) determines whether or not temperature change favors the forward or the reverse reaction.

You can also see that the sign of Spontaneity of an exothermic reaction when temperature is decreased - Chemistry Stack Exchange is irrelavent.

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