Math, asked by lalamaheshwari63, 2 months ago

b)Each angle of a quadrilateral is 2x+8°Find :
(i)the value of x
(ii) each angle of the quadrilateral
(ii) give a special name of the quadrilateral taker​

Answers

Answered by updeshsingh1973
0

each angle of the quadrilateral.

Answered by MissOxford
3

Question :

Each angle of a quadrilateral is 2x+8°Find :

(i)the value of x

(ii) each angle of the quadrilateral

(ii) give a special name of the quadrilateral taker

Answer :

\sf\pink{Given}

  • Each angle of the quadrilateral is 2x + 8°

\sf\pink{To\:find}

  • value of x = ?

  • Each angle of the quadrilateral = ?

  • Special name = ?

Rule :

Sum of all angles of a quadrilateral is 360°

Explanation :

\longrightarrow\bf{2x + 8 + 2x + 8 + 2x + 8 + 2x + 8 = 360° }

\longrightarrow\bf{ 4\times (2x + 8)  = 360° }

\longrightarrow\bf{ 8x + 32  = 360° }

\longrightarrow\bf{ 8x   = 360° - 32}

\longrightarrow\bf{ 8x   = 328 }

\longrightarrow\bf{ x   = \dfrac{328}{8} }

\longrightarrow\bf\pink{ x   = 41 }

  • Therefore value of x is 41°

Value of each angle = 2x + 8

\longrightarrow\bf{2\times 41 + 8}

\longrightarrow\bf{ 82 + 8}

\longrightarrow\bf\pink{90°}

  • Therefore value of each angle is 90°

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