.
(b) Ethane burns in oxygen to from CO, and H,O according to the equation :
2C_H + 70400, + 6H2O
If 1250 cc of oxygen is burnt with 300 cc of ethane.
Calculate :
(i) the volume of CO2 formed.
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Answer:
burns in oxygen to form CO2 and H2O according to the equation: 2C2H6 + 7O2 → 4CO2 + 6H2O
, ethane is limiting reagent.
(i) 2 x 22400 cc ethane gives, 4 x 22400 cc CO2
therefore, 300 cc ethane gives,
fraction numerator 4 space straight x space 22400 space straight x space 300 over denominator 2 space straight x space 22400 end fraction space cc space CO subscript 2
= 600 cc CO2
(ii) For 300 cc Ethane 1050 cc of O2 will be required.
Explanation:
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