Question

(b) Factorise 2 * (x - 3y) ^ 2 - 72y ^ 2​

Answer 1

step by step

2(x−3y) root 2−72y root 2

2(x−3y)(x−3y)−72y root 2

2(x(x−3y)−3y(x−3y))−72y root 2

2(x root 2−3xy−3y(x−3y))−72y root 2

2(x root 2−3xy−3xy+9y root 2)−72y root 2

2(x root 2−6xy+9y root 2)−72y root 2

2x root 2−12xy+18y root 2−72y root 2

2x root 2−12xy−54y root 2

so the answer is 2x root 2-12xy-54y root 2

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Answer 2

Step-by-step explanation:

Given :

$2( {x - 3y)}^{2} - 72 {y}^{2}$

To factorise :

The above expression.

Solution :

$2( {x - 3y)}^{2} - 72 {y}^{2} \\ \implies \: 2[( {x - 3y)}^{2} - 36 {y}^{2} ]$

$2[ ({x - 3y)}^{2} - {(6y)}^{2} ] \\ \implies \: 2(x - 3y - 6y)(x - 3y + 6y) \\ \implies \: 2(x - 9y)(x + 3y)$

Hence, the answer.