Question

b) Factorise : 64 a6– 729 b6

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Answer 1

Answer:

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Answer 2

$64a {}^{6} - 729b {}^{6} \\ (2a) { }^{6} - (3b) {}^{6 } \\ ((2a) {}^{3} ) {}^{2} - ((3b) {}^{3}) {}^{2} \\ now \: a {}^{2} - b {}^{2} =(a + b)(a - b) \\ a = (2a) {}^{3} \: and \: b \: = (3b) {}^{3 } \\ = (a + b)(a - b) \\ = ((2a) {}^{3} + (3b)^{3} ) \times ((2a)^{3} - (3b) ^{3} )$

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