Question

(b) Factorize : 27x3 + y² + z3 - 9xyz

who gives me answer fast I will mark then in brain list but it should be right​

Answer 1

Step-by-step explanation:

Given 27x³+y³+z³-9xyz

= (3x)³+y³+z³-3(3x)yz

/*By algebraic identity:

{a^{3}+b^{3}+c^{3}-3abc\\=(a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ca)}

= (3x+y+z)[(3x)²+y²+z²-(3x)y-yz-z(3x)]

=(3x+y+z)(9x²+y²+z²-3xy-yz-3zx)

Therefore,

27x^{3}+y^{3}+z^{3}-9xyz\\=(3x+y+z)(9x^{2}+y^{2}+z^{2}-3xy-yz-3zx)

Hope this helps......

Answer 2

Answer:

(3x)^3+(y)^3+(z)^3-9xyz

((3x)^3+(y)^3+(z)^3-3×3x×y×z

(3x+y+z)(9x^2+y^2+z^2-3xy-yz-3zx)