Math, asked by priyanshubhardwaj564, 2 months ago

b) factorize 8x3y3 - 2xy

Answers

Answered by zeesoftzs

1

Step-by-step explanation:

$= 8 {x}^{3} {y}^{3} - 2xy \\ = 2xy(4 {x}^{2} {y}^{2} - 1) \\ = 2xy( {(2xy)}^{2} - ( {1)}^{2} ) \\ = 2xy(2xy + 1)(2xy - 1)$

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