Question

(B) Father's age is 5 years more than four times Son's age. If the sum of 02
their ages is 55 years, Find the present ages of both of them.
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Answer 1

Answer:

Related Questions (More Answers Below) ... 2 years ago, my age was 4 and a half times my son's age. ... Subtract 5 from both sides ... The sum of the current ages of a father and his son is 60 years .

Answer 2

Given :

• Father's age is 5 years more than four times Son's age.
• If the sum of their ages is 55 years.

To Find :

• Present Ages of Son and Father .

Solution :

$\longmapsto\tt{Let\:Age\:of\:Son\:be=x}$

As Given that Father's age is 5 years more than four times Son's age. So ,

$\longmapsto\tt{Age\:of\:Father=4x+5}$

A.T.Q :

$\longmapsto\tt{x+4x+5=55}$

$\longmapsto\tt{5x+5=55}$

$\longmapsto\tt{5x=55-5}$

$\longmapsto\tt{5x=50}$

$\longmapsto\tt{x=\cancel\dfrac{50}{5}}$

$\longmapsto\tt\bf{x=10}$

Value of x is 10 ..

Therefore :

$\longmapsto\tt{Present\:Age\:of\:Son=x}$

$\longmapsto\tt\bf{10\:yrs}$

$\longmapsto\tt{Present\:Age\:of\:Father=4(10)+5}$

$\longmapsto\tt\tt{40+5}$

$\longmapsto\tt\bf{45\:yrs}$