Question

(b) Find equation of a line which passes through
point (7, 1) and parallel to the line joining the
points (2,-2) and (4,8).​

Answer 1

Answer:

Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3/5. Therefore, the slope of the line parallel to this line would have to be m = 3/5.

Answer 2

Answer:

5x - y = 34

Step-by-step explanation:

eq^n of line passing through (2, -2) and (4,8):

y - y1 = [(y2 - y1)/ (x2 - x1) ] × x - x1

y - (- 2) = { [ 8 - (-2)] / (4 - 2) } × (x - 2)

y +2 = (10/ 2) × (x -2)

y +2 = 5x - 10

5x - y = 12

it's slope (m) = - a/b = -5/ -1 = 5

eq^n of line through (7, 1) and parallel to above line : (because parallel lines have equal slopes.)

y - y3 = m( x -x3)

y - 1 = 5( x - 7)

5x - 35 = y -1

5x - y = 34