Question

(b) Find out the current through the cell and voltage across it from the given circuit diagram. ​

Answer 1

Answer:

answer will be 60 Amphere for sire

Answer 2

Answer:

The current through the cell and voltage across it is 4 A and 2 volts respectively.

Explanation:

The current and voltage across the cell will be calculated through the ohms law. Which is given as,

                    $V=IR$         (1)

Where,

V=potential difference

I=current through the circuit

R=resistance of the circuit

From the question we have,

R₁=3Ω

R₂=2Ω

R₃=10Ω

R₄=10Ω

The internal resistance of the cell(r)=0.5

The potential difference of the circuit(V)=12volt

The resistors R₁ and R₂ are connected in series. So, their net resistance will be,

$R_s=R_1+R_2$

$R_s=2+3=5\Omega$      (2)

Now the resistors R₃, R₄ and $R_s$ are connected in parallel. So,

$\frac{1}{R_p}=\frac{1}{R_3} +\frac{1}{R_4} +\frac{1}{R_s}$        (3)

By substituting all the required values in equation (3) we get;

$\frac{1}{R_p}=\frac{1}{10} +\frac{1}{10} +\frac{1}{5}$

$\frac{1}{R_p}=\frac{1+1+2}{10}$

$R_p=\frac{10}{4}$

$R_p=2.5\Omega$     (3)

The net resistance of the circuit is,

$R=R_p+r$         (4)

By substituting the values in equation (4) we get;

$R=2.5+0.5$

$R=3\Omega$    (5)

By using equation (1) the current through the cell is calculated as,

$12=I\times 3$

$I=\frac{12}{3}$

$I=4A$      (6)

The voltage across the cell(e) will also be calculated using equation (1) which is given as,

$e=I\times r$      (7)

By placing the values in equation (7) we get;

$e=4\times 0.5$

$e=2Volt$

Hence, the current through the cell and voltage across it is 4 A and 2 volt respectively.

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