Question

(B) Find the 15th term of AP: 3,8,13,...​

Answer 1

Step-by-step explanation:

Given :•

a1 = 3 , a2 = 8 , a3 = 13

n = 15

Find d :•

d = a2 - a1

d = 8 -3

d = 5

Find a15 :•

a15 = a + (n -1) d

a15 = 3 + (15 - 1) × 5

a15 = 3 + 14 × 5

a15 = 3 + 70

a15 = 73

15th term of the AP is 73

I hope it helps you

Answer 2

Answer:

15th term = 73.

Step-by-step explanation:

Given that 3, 8, 13, .........,  are in A.P

We have to find the 15th term

3, 8, 13, .........

Here  first term = a = 3

Second term = 8

Common difference = d = second term - first term

                                  = 8 - 3 = 5

aₙ = a +(n -1) d

Here a is first term, d is common difference.

$a_{15}$ = a +(15 - 1) d

    = 3+14(5)

     =3+70

     =73.

Therefore, 15th term = 73.