Question

(b) Find the angle between the lines 7x - y = 1
and 6x - y = 11 ​

Answer 1

Answer:

$7x - y = 1 \\ 7x = 1 + y \\ x = 1 + y \div 7.........(1) \\ \\ \\ \\6x - y = 11 \\ 6x = 11 + y \\ x = 11 + y \div 6.......(2)$

Answer 2

Answer:

The angle between lines $7x-y=1$ and $6x-y=11$ is $1.33^o$.

Step-by-step explanation:

Given equation of lines,

$7x-y=1$

$6x-y=11$

It is asked to find the angle between these lines.

To find angle we find the slope of each line.

$7x-y=1$

Slope: $m_1=7$

$6x-y=11$

Slope: $m_2=6$

The formula of angle between two lines is

$tan\alpha = |\frac{(m_2- m_{1} )} {(1 + m_1m_2)}|$

$tan\alpha =|\frac{(6- 7 )} {(1 +7*6)}|$

$tan\alpha =|\frac{(-1)} {(1 +42)}|$

$tan\alpha =\frac{1} {43}$

$\alpha =tan^{-1} (\frac{1}{43})$

$\alpha =1.33^o$

The angle between the given lines is $1.33^o$.

A 1-D figure which has length but no width is called as a line.

A figure in which two rays meet at a common point called the vertex is called an angle. Symbol “∠” is used to denote the angle.

The slope of a line is the ratio of difference between the y-coordinates and the x-coordinates.

To know more about angle go to the following link.

https://brainly.in/question/18979649

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