b. find the area of the shaded region. write your solutions and answers on a separate sheet of paper. use π = 3.14
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Answers
Given :
Given a rectangle with breadth and length as 16cm and 10cm along with two semicircles having their diameter 10cm which is the length of the rectangle.
To find :
We have to find the area of the shaded region.
Explaination :
Here, we are given a rectangle whose length is same as the diameter of the semicircles in it. Now, we'll find the area of the shaded region by first knowing the area of two semicircles and then subtracting this value from the area of the rectangle.
Solution :
In the rectangle :
- Length = 10cm
- Breadth = 16cm
Area of rectangle = Length (Breadth)
- Area = 10cm(16cm)
- Area = 160cm²
For the semicircle :
- Diameter = 10cm
- Radius = 5cm
Area of semircircle = πr²/2
- Area = 3.14(5cm)²/2
- Area = 3.14(25cm²)/2
- Area = 78.5cm²/2
- Area = 39.25cm²
Area of 2 semircircles = 2(πr²/2)
- Area of semircircles = 2(39.25cm²)
- Area of semircircles = 78.5cm²
Area of shaded region = Area of rectangle - Area of semircircles
- Area = 160cm² - 78.5cm²
- Area = 81.5cm²
Therefore, the area of the shaded region is 81.5cm².
Given :
Given a rectangle with breadth and length as 16cm and 10cm along with two semicircles having their diameter 10cm which is the length of the rectangle.
To find :
We have to find the area of the shaded region.
Explaination :
Here, we are given a rectangle whose length is same as the diameter of the semicircles in it. Now, we'll find the area of the shaded region by first knowing the area of two semicircles and then subtracting this value from the area of the rectangle.
Solution :
In the rectangle :
Length = 10cm
Breadth = 16cm
Area of rectangle = Length (Breadth)
Area = 10cm(16cm)
Area = 160cm²
For the semicircle :
Diameter = 10cm
Radius = 5cm
Area of semircircle = πr²/2
Area = 3.14(5cm)²/2
Area = 3.14(25cm²)/2
Area = 78.5cm²/2
Area = 39.25cm²
Area of 2 semircircles = 2(πr²/2)
Area of semircircles = 2(39.25cm²)
Area of semircircles = 78.5cm²
Area of shaded region = Area of rectangle - Area of semircircles
Area = 160cm² - 78.5cm²
Area = 81.5cm²
Therefore, the area of the shaded region is 81.5cm².