Question

b)
Find the length of the conductor which is moving with a speed of 10 m/s in the direction
perpendicular to the direction of magnetic field of induction 0.8T, if it induces an emf of 8V
between the ends of the conductor.​

Answer 1

Answer:

L = 10 m

Explanation:

v = 10 m/s ,  B = 0.8T ,  v = 8 v  , Θ = 90^o

ε = vbL sinΘ ⇒ L = ε / vb sinΘ ⇒ L = 8 / 10x0.8xsin90^o  

L = 10 m

Answer 2

Answer:

1m

Explanation:

v = 10m/s , B = 0.8T, and e = 8v ,l = ? using, e= blv 8= 0.8(l)10. =1m or 100cm 0.8(10) = 8 then , 8/8 = 1m or 100cm