Question

b) Find the mean and median of the data 49,48,15,20,28,17,14 and 110
​

Answer 1

Answer:

The sum of number

49+48+15+20+28+17+14+110

=> 301

.

. . 301/8 = 37.62

The mean is 37.62...

Answer 2

${\boxed{\mathfrak{ Answer}}}$

Meαn

$\tt \frac {49 + 48 + 15 + 20 + 28 + 17 + 14 + 10}{8}$

= $\tt \frac {201}{8}$ = ${\boxed{\tt{25,125}}}$

Mediαn

${\boxed{\tt{48}}}$

___________________________

${\boxed{\mathfrak{{\pink{B}{\blue{y}:{\red{E}{\blue{m}{\green{p}{\blue{t}{\purple{y}{\red{z}{\pink{z}}}}}}}}}}}}}$