(b) Find the mean free path of helium molecules at a
temperature of OC and a pressure of 760 mm Hg.
Coefficient of viscosity is 1.3 x 10- Nm-4 s. Density
of helium is 1.1786 kg m-
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Calculate the means free path of nitrogen molecule at 27
o
C when pressure is 1.0 atm. Given, diameter of nitrogen molecule =1.5
A
o
, k
B
=1.38×10
−23
J K
−1
. If the average speed of nitrogen molecule is
C=27+273=300K.
P=1atm =1.01×10
5
N m
−2
, d=1.5
A
o
=1.5×10
−10
m,
k
B
=1.38×10
−23
J K
−1
,λ=?
From λ=
2
πd
2
p
k
B
T
=
1.414×3.14(1.5×10
−10
)
2
×1.01×10
5
1.38×10
−23
×300
=4.1×10
−7
m
Time interval between two successive collisions
t=
speed
distance
=
v
λ
=
675
4.1×10
−7
=0.6×10
−9
s
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Explanation:
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