Question

(b)Find the perimeter of a rhombus whose diagonals are 16cm and 12cm

Answer 1

it's 40 cm.....
one of the method of doing this question is this......
Hope it helps....

Answer 2

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Here, AC = 16 cm
BD = 15 cm

Now, OA = 16 cm / 2 or 8 cm

And, OB = 12 cm / 2 or 6 cm

As we know that diagonal of rhombus bisect at 90°

H² = B² + P²

AB² = OA² + OB²

AB² = 8² + 6²

AB = √( 64 + 36 )

AB = 10

Now, as all sides of rhombus are equal so

Perimeter = 4( side )

= 4*10 cm = 40 cm

Hope it helps