(b)Find the perimeter of a rhombus whose diagonals are 16cm and 12cm
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Answered by
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D1 = 16 cm
D2 = 12 cm
Side of rhombus = sqrt [ (D1/2)^2 + (D2 /2)^2]
= sqrt [ ( 16 /2)^2 + (12/2)^2]
= sqrt ( 8^2 + 6^2)
= sqrt ( 64 + 36)
= sqrt ( 100)
= 10 cm
Perimeter = 4 × side
= 4 × 10
= 40 cm
D2 = 12 cm
Side of rhombus = sqrt [ (D1/2)^2 + (D2 /2)^2]
= sqrt [ ( 16 /2)^2 + (12/2)^2]
= sqrt ( 8^2 + 6^2)
= sqrt ( 64 + 36)
= sqrt ( 100)
= 10 cm
Perimeter = 4 × side
= 4 × 10
= 40 cm
Answered by
2
ans :is 40
to find this apply formulae p=√12*12+16*16/2
to find this apply formulae p=√12*12+16*16/2
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