(b) Find the perpendicular distance from the point
(-1, 2) from the line x + 3y - 4 = 0.
5,5
Answers
Answered by
2
Answer:
x−
3
y+4=0
Perpendicular distance is =
∣
∣
∣
∣
∣
a
2
+b
2
ax+by+c
∣
∣
∣
∣
∣
Given point is (1,2)
Therefore perpendicular distance, d=
∣
∣
∣
∣
∣
∣
∣
1
2
+(
3
)
2
1×1−
3
×2+4
∣
∣
∣
∣
∣
∣
∣
⇒d=
2
5−2
3
Step-by-step explanation:
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Answered by
2
Answer:
Answer:
x−
3
y+4=0
Perpendicular distance is =
∣
∣
∣
∣
∣
a
2
+b
2
ax+by+c
∣
∣
∣
∣
∣
Given point is (1,2)
Therefore perpendicular distance, d=
∣
∣
∣
∣
∣
∣
∣
1
2
+(
3
)
2
1×1−
3
×2+4
∣
∣
∣
∣
∣
∣
∣
⇒d=
2
5−2
3
Step-by-step explanation:
Hope this answer will help you.
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