Question

(b) Find the perpendicular distance from the point
(-1, 2) from the line x + 3y - 4 = 0.
5,5​

Answer 1

Answer:

x−

3

y+4=0

Perpendicular distance is =

∣

∣

∣

∣

∣

a

2

+b

2

ax+by+c

∣

∣

∣

∣

∣

Given point is (1,2)

Therefore perpendicular distance, d=

∣

∣

∣

∣

∣

∣

∣

1

2

+(

3

)

2

1×1−

3

×2+4

∣

∣

∣

∣

∣

∣

∣

⇒d=

2

5−2

3

Step-by-step explanation:

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Answer 2

Answer:

Answer:

x−

3

y+4=0

Perpendicular distance is =

∣

∣

∣

∣

∣

a

2

+b

2

ax+by+c

∣

∣

∣

∣

∣

Given point is (1,2)

Therefore perpendicular distance, d=

∣

∣

∣

∣

∣

∣

∣

1

2

+(

3

)

2

1×1−

3

×2+4

∣

∣

∣

∣

∣

∣

∣

⇒d=

2

5−2

3

Step-by-step explanation:

Hope this answer will help you.