(b) Find the value of k. 2^12 ÷ 2^k/2 = 32
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Answer:
k=2 and k=1/2
Step-by-step explanation:
x²−2(5+2k)k+3(7+10k)=0
⇒ Here, a=1,b=−2(5+2k),c=3(7+10k)
⇒ It is given that roots are real and equal.
∴ b²−4ac=0
⇒ [−2(5+2k)] ²−4(1)[3(7+10k)]=0
⇒ 4(25+20k+4k²)−4(21+30k)=0
⇒ 100+80k+16k
2
−84−120k=0
⇒ 16k²−40k+16=0
⇒ 2k²−5k+2=0
⇒ 2k²−4k−k+2=0
⇒ 2k(k−2)−1(k−2)=0
⇒ (k−2)(2k−1)=0
⇒ k−2=0 and 2k−1=0
∴ k=2 and k=1/2
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