Question

(b) Find the value of: sin²30' cos²45' + 4tan² 30' + sin²90°+cos³0​

Answer 1

Answer:

sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0°

sin²30° = (1/2)² = 1/4

cos²45° = (1/√2)² = 1/2

tan²30° = (1/√3)² = 1/3

sin²90° = 1

cos²90° = 0

cos²0° = 1

= (1/4)(1/2)  + 4(1/3)   + (1/2)(1) - 2*0  + (1/24)1

= 1/8  + 4/3  + 1/2  + 1/24

= (3 + 32 + 12 + 1)/24

= 48/24

= 2

sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0° = 2

Learn more:

If sin θ + cos θ = 2 , then evaluate : tan θ + cot θ - Brainly.in

brainly.in/question/7871635

cosec(90+x)+cot(90+x)/cosec(90-x)+tan(180-x)+tan(180+x)+

Step-by-step explanation:

Answer 2

Answer:

Explanation

sin²30= (1/2)² =1/4

cos²45=(1/√2)²=1/2

tan²30=(1/√3)

so, 4tan²30 = 4×1/3= 4/3

sin²90=(1)²=1

cos³0=(1)³=1

so, sin²30.cos²45 +4tan²30 +sin²90 +cos³0

1/4 ×1/2+4/3+1+1

3+32+24+24/24

83/24

3.45

this is the answer. hope it helps.