Question

(b) Find the value(s) of m for which the given quadratic equation has equal roots.
x + 2(m - 1)x + m + 5) = 0​

Answer 1

Answer:

D = 0

b^2 - 4ac = 0

2(m - 1)^2 - 4×1×(m + 5) = 0

4m^2 + 4 -8m -4m - 20 = 0

4m^2 - 12m -16 = 0

4m^2 -16m + 4m - 16 = 0

4m(m - 4)+4(m - 4 ) = 0

( 4m + 4)( m - 4) = 0

m = -1 & 4