Question

b) Find the velocity of a bullet of mass 10g which is fired from a pistol of

mass 1.5kg. The recoil velocity of the pistol is 2.5 m/s. Pls tell the correct answer. The most accurate answer will be marked the brainliest​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The final velocity of bullet is -375 m/s

Explanation:

Given ,

mass of bullet (m1) = 10g = 10/1000 kg = 1/100kg

mass of gun (m2 ) = 1.5 kg

initial velocity of bullet (u1) = 0m/s

initial velocity of gun(u2) = 0m/s

Final velocity of bullet ( v1) = ?

Final velocity of gun (v2) = 2.5 m/s

From Law of conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

1/100 x 0 + 1.5 x 0 = 1/100 x v1 + 1.5 x 2.5

0 + 0 = v1 / 100 + 3.75

0 = v1/100 + 3.75

-3.75 = v1/100

-3.75 x 100 = v1

-375 m/s = v1

The final velocity of bullet is -375m/s