Question

(b) Find the volume of solid drawn in below figure:​

Answer 1

$⍟ \: \underline{ \red{ \rm SOLUTION \: \: : }}$

The Given figure can be breaked into 2 cuboids.

where, we can easily find its volume by adding.

Let's go some further.

for Diagrammatic Explanation, refer the attachment.

and we are going to use only 1 formula .i.e.,

$\boxed{☞ \: \red{ \colorbox{pink}{volume \: \: of \: \: cuboid = lbh}}}$

From, Cuboid 1 :

Length = 6cm

Breadth = 9cm

Height = 3cm

by applying the values,

$\rm (volume \: \: of \: \: cuboid)_{1} = 6 \times 9 \times 3$

$\rm (volume \: \: of \: \: cuboid)_{1} = 18 \times 9$

$\boxed{ \green{ \rm (volume \: \: of \: \: cuboid)_{1} }= \color{gold}\bf{162 \: {cm}^{3} }} \to{ \rm eq(1)}$

From, Cuboid 2 :

Length = 7cm

Breadth = 9cm

Height = 8 - 6 = 2cm

by applying the values,

$\rm (volume \: \: of \: \: cuboid)_{2} = 7 \times 9 \times 2$

$\rm (volume \: \: of \: \: cuboid)_{2} = 14 \times 9$

$\boxed{ \orange{ \rm (volume \: \: of \: \: cuboid)_{2}} = \color{green} \bf 126 \: {cm}^{3} } \to{ \rm eq(2)}$

Volume of the Given Figure is given by :

$\blue ➠ \: \: { \colorbox{springgreen}{eq(1) + eq(2)}}$

$➠ \: \: 162 + 126$

$➠ \: \orange{ \bf{\: \: 288 \: {cm}^{3} }}$

$- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -$

$\rm \therefore \: \: the \: \: \: volume \: \: \: of \: \: the \: \: give n\: \: \: figure \: \: \:$

$\pink{ \rm \: is \: \: \: 288 \: {cm}^{3} }$