(b) Find two consecutive even numbers such that one-quarter of the smaller exceeds one-fifth of the larg
by 4.
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Step-by-step explanation:
Let smaller number be 'x'
Therefore, the consecutive larger number is x+1
According to given conditions
x/4 - x+1/5 = 4
Equalizing the denominators
5x/20 - 4(x+1)/20 = 4
5x -4x -4 = 4*20 (20 from one side of equation moves to other side for multiplication)
x-4= 80
Therefore x = 80+4
= 84 is the smaller number
Now,
x+1 = 84+1
= 85 is the larger number
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