Question

(b) Find two consecutive even numbers such that one-quarter of the smaller exceeds one-fifth of the larg
by 4.​

Answer 1

Step-by-step explanation:

Let smaller number be 'x'

Therefore, the consecutive larger number is x+1

According to given conditions

x/4 - x+1/5 = 4

Equalizing the denominators

5x/20 - 4(x+1)/20 = 4

5x -4x -4 = 4*20 (20 from one side of equation moves to other side for multiplication)

x-4= 80

Therefore x = 80+4

= 84 is the smaller number

Now,

x+1 = 84+1

= 85 is the larger number