Math, asked by Queenzi, 9 months ago

*B. Find two consecutive positive numbers
such that the sum of their squares is equal to
113.​

Answers

Answered by Anonymous
3

Answer:

The numbers are 7 and 8.

Explanation:

Let the two numbers be x and x + 1. Then:

x^2 + (x +1)^2 = 113

x^2 + x^2 + 2x + 1 = 113

2x^2 + 2x - 112 = 0

x^2 + x - 56 = 0

(x + 8)(x - 7) = 0

x = -8 or 7

Since the numbers are positive, the two consecutive numbers will be 7 and 8.

Hopefully this will help you...

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