Question

b.
For exams, there are three sets of math papers: 128 of Set 1, 114 of Set 2, and 38
of Set 3. If there are 14 teachers to check all the papers, how many papers can each
correct if divided equally?​

Answer 1

Answer:

Add three sets

Set 1 + Set 2 + Set 3 = 128+114+38 = 280

Then, divide the 280 by 14

The answer is 20