Question

(b) From a solid wooden cylinder of height 28 cm and diameter 6 cm. Two conical cavities are hollowed out. The diameters of the cone is also 6 cm and height is 10.5 cm.
Taking
\pi = frac{22}{7} , find the volume of the remaining solid.​

Answer 1

Answer :

• Volume of remaining Solid is 594cm³

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Given :

• Height of cylinder = 28cm
• Diameter of cylinder = 6cm
• Radius of cone = 3cm

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• Diameter of cone = 6cm
• Radius of cone = 3cm
• Height of cone =10.5cm

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To find :

• Find the volume of the remaining solid.

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Solution :

• In the Question Height and diameter of the cylinder and cone is given. Firstly We will find the radius of the cylinder and Cone. We will Find the volume of cylinder by Using height and radius and then in the same way we will find the volume of the Cone. Let 'r' be radius and 'h' be height. And Then Find the Volume of remaining Solid.

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${ \underline{ \boxed{ \bf{\red{Volume \: of \: cylinder =\pi {r}^{2} h}}}}} \:$

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➤ 22/7 × 3 × 3 × 28

➤ 22 × 3 × 3 × 4

➤ 792 cm³ ____❶

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$\underline { \boxed{ \bf{\red{Volume \: of \: Cone = \dfrac{1}{3} \pi {r}^{2} h}}}}$

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➤ 1/3 × 22/7 × 3 × 3 × 10.5

➤ 1/3 × 22/7 × 8 × 10.5

➤ 693/7

➤ 99 cm³ _____❷

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Volume of Remaining Solid

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➤ 792 - 99 [❶ from ❷]

➤ 594cm³

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$\therefore{\underline { \boxed{ \bf{\blue{Volume \: of \: remaining~solid~is~594{cm}^{3} }}}}}$

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