(b) From the given figure, find the angles of the parallelogram ABCD.
Answers
Answer:
Answer:x = 30 ; 2x = 60
Answer:x = 30 ; 2x = 60Step-by-step explanation:
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADC
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADCx + 2x + 90 = 180. ( : Angle sum property of triangles)
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADCx + 2x + 90 = 180. ( : Angle sum property of triangles)3x + 90 = 180
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADCx + 2x + 90 = 180. ( : Angle sum property of triangles)3x + 90 = 1803x = 180-90
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADCx + 2x + 90 = 180. ( : Angle sum property of triangles)3x + 90 = 1803x = 180-903x = 90
Answer:x = 30 ; 2x = 60Step-by-step explanation:We can see that line segment CA is perpendicular bisector, so angle formed is 90°The triangle ADCx + 2x + 90 = 180. ( : Angle sum property of triangles)3x + 90 = 1803x = 180-903x = 90x = 90/3 = 30