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(b) From the sum of 4 + 3x and 5 - 4x + 2x^2, subtract the sum of 3x^2 - 5x and -x^2+2x+5
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[(4 + 3x) + (5 - 4x + 2x^2)] - [(3x^2 - 5x) + (-x^2 + 2x + 5)]
= (4 + 3x + 5 - 4x + 2x^2) - (3x^2 - 5x - x ^2 + 2x + 5)
= (2x^2 - x + 9) - (2x^2 - 3x + )
= 2x^2 - x + 9 - 2x^2 + 3x - 5
= 2x + 4
Step-by-step explanation:
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