(b) Give balanced Reaction
Ethane react with Bromine molecules.
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Well, ethylene reacts with bromine according to the following reaction…
H2C=CH2(g)+Br2(l)→BrH2C−CH2Br(l)
But your scenario specifies BROMINE solution, and this is likely a solution of bromine in WATER…and so given the olefin, the first reaction would be with the bromine electrophile…
H2C=CH2(g)+Br2(aq)→BrH2C−CH+2+Br−
But the carbocationic product (possibly a three-membered bromonium ion ring) would likely react with the water solvent, the which is present in abundance, to give the halohydrin as shown …
BrH2C−CH+2+H2O(l)→BrH2C−CH2OH+H+
And so we write overall…
H2C=CH2(g)+Br2(aq)+H2O(l)→BrH2C−CH2OH(aq)+HBr(aq)
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