Question

(b) Given that tan0=5/12 and 0 is an acute angle, find sin0 and Cos0​

Answer 1

Answer:

1+tan^2theta= sec^2theta

1+25/144=sec^2 theta

sec^2 theta=169/144

sec theta= 13/12

or cos theta=12/13

Now, tan theta=sin theta/ cos theta

sin theta= tan theta× cos theta

sin theta= 5/13

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Answer 2

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